Question

what value of y is a solution to this equation?
$-3 = \frac{y - 3}{2}$
$y = -3$ $y = 1$

Explanation:

Step1: Multiply both sides by 2

To eliminate the denominator, we multiply both sides of the equation \(-3 = \frac{y - 3}{2}\) by 2. This gives us \(2\times(-3)=2\times\frac{y - 3}{2}\), which simplifies to \(-6 = y - 3\).

Step2: Add 3 to both sides

To solve for \(y\), we add 3 to both sides of the equation \(-6 = y - 3\). So, \(-6 + 3 = y - 3 + 3\), which simplifies to \(-3 = y\).

We can also check by substituting the given values:

• For \(y=-3\): Substitute into \(\frac{y - 3}{2}\), we get \(\frac{-3 - 3}{2}=\frac{-6}{2}=-3\), which matches the left - hand side.
• For \(y = 1\): Substitute into \(\frac{y - 3}{2}\), we get \(\frac{1-3}{2}=\frac{-2}{2}=-1

eq - 3\).

Answer:

\(y=-3\) (the option with \(y = - 3\))