QUESTION IMAGE
Question
- a) what value of x will make the expression $6x + 3(x + 4)$ equal to -6 ? b) 48 ?
Part (a)
Step 1: Set up the equation
We set the expression \(6x + 3(x + 4)\) equal to \(-6\), so we have the equation:
\[6x + 3(x + 4)=-6\]
Step 2: Distribute the 3
Using the distributive property \(a(b + c)=ab+ac\), we distribute the 3 in \(3(x + 4)\):
\[6x+3x + 12=-6\]
Step 3: Combine like terms
Combine the \(x\)-terms \(6x\) and \(3x\):
\[9x+12=-6\]
Step 4: Subtract 12 from both sides
Subtract 12 from each side of the equation to isolate the term with \(x\):
\[9x=-6 - 12\]
\[9x=-18\]
Step 5: Divide by 9
Divide both sides by 9 to solve for \(x\):
\[x=\frac{-18}{9}\]
\[x = - 2\]
Step 1: Set up the equation
We set the expression \(6x + 3(x + 4)\) equal to \(48\), so we have the equation:
\[6x + 3(x + 4)=48\]
Step 2: Distribute the 3
Using the distributive property \(a(b + c)=ab + ac\), we distribute the 3 in \(3(x + 4)\):
\[6x+3x + 12=48\]
Step 3: Combine like terms
Combine the \(x\)-terms \(6x\) and \(3x\):
\[9x+12=48\]
Step 4: Subtract 12 from both sides
Subtract 12 from each side of the equation to isolate the term with \(x\):
\[9x=48 - 12\]
\[9x=36\]
Step 5: Divide by 9
Divide both sides by 9 to solve for \(x\):
\[x=\frac{36}{9}\]
\[x = 4\]
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(a):
\(x=-2\)