Question

. what is the value of x? the left and get all the x terms on the right equation. = 6x - 12 = 6x - 12 = 6x - 12 + 2x =

Explanation:

Step1: Identify like terms

We have \(6x - 12+2x\). The like terms are \(6x\) and \(2x\).

Step2: Combine like terms

Combine \(6x\) and \(2x\): \(6x + 2x=8x\). The \(- 12\) remains as it is. So the expression becomes \(8x-12\). But wait, maybe the left side was equal to the right side before adding \(2x\). Wait, looking at the structure, maybe we are adding \(2x\) to \(6x - 12\). So \(6x+2x-12\). Combining \(6x\) and \(2x\) gives \(8x\), so the result is \(8x - 12\)? Wait, no, maybe the left side was equal to \(6x - 12\) and then we add \(2x\) to the right side? Wait, the last line is "= + 2x" above the line, and then the box. Wait, maybe the equation is such that we have to combine \(6x\) and \(2x\). So \(6x+2x = 8x\), and then - 12? Wait, no, maybe the original right side is \(6x - 12\) and we add \(2x\) to it, so \(6x+2x-12=8x - 12\)? But maybe the -12 is not there? Wait, the first three lines are "= 6x - 12", then a line with "+2x" below, so we are adding \(2x\) to \(6x - 12\). So combining the \(x\) terms: \(6x+2x = 8x\), and the constant term is - 12. But maybe the -12 is not part of the addition? Wait, no, the first three lines are "= 6x - 12", then a horizontal line with "+2x" above it, so we are adding \(2x\) to \(6x - 12\). So \(6x+2x-12=8x - 12\)? But maybe the -12 is a mistake, and we just need to add \(6x\) and \(2x\). If that's the case, \(6x + 2x=8x\). Given the context, maybe the -12 is not part of the terms being added, and we just need to combine \(6x\) and \(2x\). So the answer is \(8x - 12\) or \(8x\)? Wait, the first three lines are "= 6x - 12", then a line with "+2x" below, so the operation is \(6x - 12+2x\). Combining like terms: \(6x+2x=8x\), so \(8x - 12\). But maybe the -12 is a typo, and we just have \(6x+2x\). If we assume that we are only adding the \(x\) terms, then \(6x + 2x = 8x\). Given the box, maybe the answer is \(8x - 12\) or \(8x\). But looking at the structure, maybe the -12 is not part of the addition, and we are just combining \(6x\) and \(2x\). So \(6x+2x = 8x\).

Answer:

\(8x - 12\) (or \(8x\) if the -12 is not included, but based on the given lines, it's \(8x - 12\))