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Question
- if \\( \angle abd = 2x + 7 \\) and \\( \angle dbc = 8x + 13 \\), what is the value of x?
Step1: Use the linear - pair relationship
Since \(\angle ABD\) and \(\angle DBC\) form a linear pair, \(\angle ABD+\angle DBC = 180^{\circ}\).
Given \(\angle ABD=2x + 7\) and \(\angle DBC=8x + 13\), we substitute these into the equation: \((2x + 7)+(8x + 13)=180\).
Step2: Simplify the left - hand side of the equation
Combine like terms: \(2x+8x+7 + 13=180\), which simplifies to \(10x+20 = 180\).
Step3: Solve for \(x\)
Subtract 20 from both sides: \(10x+20-20=180 - 20\), so \(10x=160\).
Divide both sides by 10: \(x=\frac{160}{10}\).
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\(x = 16\)