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what is the value of b? h 3 j b i b =

Question

what is the value of b?
h
3
j
b
i
b =

Explanation:

Step1: Identify triangle type

The triangle \( \triangle HIJ \) has two equal angles (at \( I \) and \( J \)), so it's isosceles.

Step2: Apply isosceles triangle property

In an isosceles triangle, sides opposite equal angles are equal. Side \( HI = 3 \), and side opposite \( \angle J \) (which is equal to \( \angle I \)) is \( HI \), while side opposite \( \angle I \) is \( HJ \)? Wait, no—wait, angle at \( I \) and angle at \( J \) are equal, so sides opposite them: side opposite \( \angle I \) is \( HJ \)? Wait, no, let's label: vertex \( I \), \( H \), \( J \). Angle at \( I \) ( \( \angle I \)) and angle at \( J \) ( \( \angle J \)) are equal. So side opposite \( \angle I \) is \( HJ \), side opposite \( \angle J \) is \( HI \). Wait, no, \( HI \) is length 3, and side \( IJ \) is \( b \). Wait, maybe I mixed up. Wait, angle at \( I \) and angle at \( J \) are equal, so the sides opposite them: side opposite \( \angle I \) is \( HJ \), side opposite \( \angle J \) is \( HI \). Wait, no, \( HI \) is from \( H \) to \( I \), length 3. \( IJ \) is from \( I \) to \( J \), length \( b \). \( HJ \) is from \( H \) to \( J \). Wait, no—wait, the angles at \( I \) and \( J \) are equal, so the sides opposite those angles are equal. The side opposite \( \angle I \) is \( HJ \), and the side opposite \( \angle J \) is \( HI \). Wait, no, that can't be. Wait, maybe the equal angles are at \( I \) and \( H \)? No, the red arcs are at \( I \) and \( J \). Wait, maybe I made a mistake. Wait, in triangle \( HIJ \), angles at \( I \) and \( J \) are equal (red arcs), so it's isosceles with \( HI = HJ \)? No, wait, \( HI \) is length 3, and the side \( IJ \) is \( b \), and the side \( HI \) is 3. Wait, no—wait, angle at \( I \) and angle at \( J \) are equal, so the sides opposite them: side opposite \( \angle I \) is \( HJ \), side opposite \( \angle J \) is \( HI \). Wait, no, \( HI \) is adjacent to \( \angle I \). Wait, maybe the equal angles are at \( I \) and \( H \)? No, the red arcs are at \( I \) and \( J \). Wait, perhaps the triangle has \( \angle I = \angle J \), so sides opposite: \( HI \) is opposite \( \angle J \), and \( HJ \) is opposite \( \angle I \). Wait, no, \( HI \) is length 3, so if \( \angle I = \angle J \), then side opposite \( \angle I \) (which is \( HJ \)) equals side opposite \( \angle J \) (which is \( HI \)). Wait, that would mean \( HJ = HI = 3 \), but the side we need is \( IJ = b \). Wait, maybe I got the angles wrong. Wait, the red arcs are at \( I \) and \( J \), so \( \angle I = \angle J \), so the sides opposite are \( HJ \) and \( HI \)? No, \( HI \) is from \( H \) to \( I \), \( HJ \) is from \( H \) to \( J \), \( IJ \) is from \( I \) to \( J \). So in triangle \( HIJ \), vertices: \( H \) (top), \( I \) (bottom left), \( J \) (bottom right). Angles at \( I \) and \( J \) are equal (red arcs). So sides: \( HI \) (left side, length 3), \( HJ \) (right side), \( IJ \) (base, length \( b \)). In an isosceles triangle, sides opposite equal angles are equal. So angle at \( I \) is opposite \( HJ \), angle at \( J \) is opposite \( HI \). Therefore, \( HJ = HI \). Wait, \( HI = 3 \), so \( HJ = 3 \). But that's not \( b \). Wait, maybe the equal angles are at \( I \) and \( H \)? No, the red arcs are at \( I \) and \( J \). Wait, maybe I misread the triangle. Wait, the left side is \( HI = 3 \), the base is \( IJ = b \), and the right side is \( HJ \). The angles at \( I \) and \( J \) are equal, so the sides opposite them: angle at \( I \) is opposite \( HJ \), angle at \( J \) is opposite \( HI \).…

Answer:

\( 3 \)