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Question
what is the value of f(-3) for each function?
- f(x) = 4x - 9
- f(x) = \frac{1}{3}x + 13
- f(x) = -2x - 11
Step1: Solve for \( f(-3) \) in \( f(x) = 4x - 9 \)
Substitute \( x = -3 \) into the function: \( f(-3)=4(-3)-9 \)
Calculate: \( 4(-3)= -12 \), then \( -12 - 9 = -21 \)
Step2: Solve for \( f(-3) \) in \( f(x)=-\frac{1}{3}x + 13 \)
Substitute \( x = -3 \) into the function: \( f(-3)=-\frac{1}{3}(-3)+13 \)
Calculate: \( -\frac{1}{3}(-3)=1 \), then \( 1 + 13 = 14 \)
Step3: Solve for \( f(-3) \) in \( f(x)=-2x - 11 \)
Substitute \( x = -3 \) into the function: \( f(-3)=-2(-3)-11 \)
Calculate: \( -2(-3)=6 \), then \( 6 - 11 = -5 \)
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- \( f(-3) = -21 \)
- \( f(-3) = 14 \)
- \( f(-3) = -5 \)