Question

what is the solution of the system of equations?
4x + 2y = -1
3x + 4y = 3
show your work here
(1, 2/3) (-1, 2/3)
(1, 3/2) (-1, 3/2)

Explanation:

Step1: Eliminate y by multiplying first equation

Multiply \(4x + 2y=-1\) by 2: \(8x + 4y=-2\)

Step2: Subtract second equation from new equation

Subtract \(3x + 4y = 3\) from \(8x + 4y=-2\):
\((8x + 4y)-(3x + 4y)=-2 - 3\)
\(5x=-5\)
\(x = - 1\)

Step3: Substitute x into first equation

Substitute \(x=-1\) into \(4x + 2y=-1\):
\(4(-1)+2y=-1\)
\(-4 + 2y=-1\)
\(2y=3\)
\(y=\frac{3}{2}\)

Answer:

\((-1,\frac{3}{2})\)