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what is the solution set to the inequality \\(5(x - 2)(x + 4) > 0\\)? \…

Question

what is the solution set to the inequality \\(5(x - 2)(x + 4) > 0\\)?

\\(\\{x \mid x > -4 \text{ and } x < 2\\}\\)
\\(\\{x \mid x < -4 \text{ or } x > 2\\}\\)
\\(\\{x \mid x < -2 \text{ or } x > 4\\}\\)
\\(\\{x \mid x > -2 \text{ or } x < 4\\}\\)

Explanation:

Find the boundary points of the inequality

$$ 5(x - 2)(x + 4) = 0 \implies x = 2 \quad \text{or} \quad x = -4 $$

Determine the sign of the quadratic expression on each interval

$$ LATEXBLOCK0 $$

State the solution set for the strict inequality

$$ \{x \mid x < -4 \text{ or } x > 2\} $$

Answer:

  • {x | x &gt; -4 and x &lt; 2}
  • {x | x &lt; -4 or x &gt; 2} (Correct answer)
  • {x | x &lt; -2 or x &gt; 4}
  • {x | x &gt; -2 or x &lt; 4}