QUESTION IMAGE
Question
what is the solution set to the inequality \\(5(x - 2)(x + 4) > 0\\)?
\\(\\{x \mid x > -4 \text{ and } x < 2\\}\\)
\\(\\{x \mid x < -4 \text{ or } x > 2\\}\\)
\\(\\{x \mid x < -2 \text{ or } x > 4\\}\\)
\\(\\{x \mid x > -2 \text{ or } x < 4\\}\\)
Find the boundary points of the inequality
$$
5(x - 2)(x + 4) = 0 \implies x = 2 \quad \text{or} \quad x = -4
$$
Determine the sign of the quadratic expression on each interval
$$
LATEXBLOCK0
$$
State the solution set for the strict inequality
$$
\{x \mid x < -4 \text{ or } x > 2\}
$$
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- {x | x > -4 and x < 2}
- {x | x < -4 or x > 2} (Correct answer)
- {x | x < -2 or x > 4}
- {x | x > -2 or x < 4}