Question

what is the solution set of $x - 9 \leq 0$?
\bigcirc a. $x \leq -9$
\bigcirc b. $x \leq 9$
\bigcirc c. $x \geq -9$
\bigcirc d. $x \geq 9$

Explanation:

Step1: Isolate x

Add 9 to both sides of $x - 9 \leq 0$:
$x - 9 + 9 \leq 0 + 9$

Step2: Simplify

$x \leq 9$

Answer:

b. $x \leq 9$