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Question
what are the solution(s) to the quadratic equation $x^2 - 25 = 0$? $x = 5$ and $x = -5$; $x = 25$ and $x = -25$; $x = 125$ and $x = -125$; no real solution
Step1: Isolate the squared term
$x^2 - 25 = 0 \implies x^2 = 25$
Step2: Apply square root property
$x = \pm\sqrt{25} \implies x = \pm5$
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$x = 5$ and $x = -5$