Question

what is the solution to the linear equation?
$2.8y + 6 + 0.2y = 5y - 14$
$\circ\\ y = -10$
$\circ\\ y = -1$
$\circ\\ y = 1$
$\circ\\ y = 10$

Explanation:

Step1: Combine like terms on left

Combine \(2.8y\) and \(0.2y\): \(2.8y + 0.2y = 3y\), so equation becomes \(3y + 6 = 5y - 14\).

Step2: Subtract \(3y\) from both sides

\(3y - 3y + 6 = 5y - 3y - 14\), simplifies to \(6 = 2y - 14\).

Step3: Add 14 to both sides

\(6 + 14 = 2y - 14 + 14\), gives \(20 = 2y\).

Step4: Divide both sides by 2

\(\frac{20}{2} = \frac{2y}{2}\), so \(y = 10\).

Answer:

D. \(y = 10\)