Question

what is the radius of a globe that has a volume of 113.10 in³?
the radius is
(round to the nea needed.)
in.
in³.
in².

Explanation:

Step1: Use sphere volume formula

Volume of sphere: $V = \frac{4}{3}\pi r^3$
Given $V = 113.10\ \text{in}^3$, substitute: $113.10 = \frac{4}{3}\pi r^3$

Step2: Solve for $r^3$

Multiply both sides by $\frac{3}{4\pi}$:
$r^3 = \frac{113.10 \times 3}{4\pi} = \frac{339.3}{12.566} \approx 27$

Step3: Find cube root of $r^3$

$r = \sqrt[3]{27} = 3$

Answer:

3 in.