Question

what will be printed when we run the following code snippet and the user enters five?
try:
userinput = input(\enter an int >0: \)
value = 10/int(userinput)
print(1, end = \ \)
except valueerror:
print(2, end = \ \)
except zerodivisionerror:
print(3, end = \ \)
else:
print(4, end = \ \)
finally:
print(5, end = \ \)

Explanation:

Step1: Analyze the input

The user enters 'five', which cannot be converted to an integer. So int(userInput) will raise a ValueError.

Step2: Check the exception handling

Since a ValueError is raised, the except ValueError block will execute. It prints 2.

Step3: Check the finally block

The finally block always executes. It prints 5.

Answer:

2 5