Question

what is the output of the following code?
double x = 5.5;
int y = (int)x;
system.out.println(\x is \ + x + \ and y is \ + y);
a) x is 5.5 and y is 5.
b) x is 6 and y is 6.
c) x is 5 and y is 6.
d) x is 6.0 and y is 6.0.
e) x is 5.5 and y is 5.0.

Explanation:

1. First, the variable x is declared as a double with the value 5.5, so when printed, x will show 5.5.
2. Then, y is declared as an int and is assigned the value of x after casting x to an int. Casting a double value 5.5 to an int truncates the decimal part, so y becomes 5.
3. Looking at the options, option A ("x is 5.5 and y is 5.") matches this result. Option E incorrectly shows y as 5.0 (but y is an int, so it should be 5 without the .0), and the other options have incorrect values for x or y.

Answer:

A. x is 5.5 and y is 5.