Question

what is the order of rotational symmetry and the angle of rotation for the given figure? order ( = 3 ), angle of rotation ( = 60^{circ} ) order ( = 3 ), angle of rotation ( = 120^{circ} ) order ( = 60^{circ} ), angle of rotation ( = 3 ) order ( = 120^{circ} ), angle of rotation ( = 3 )

Explanation:

Step1: Recall the formula for the angle of rotation

The formula for the angle of rotation of a regular polygon is $\frac{360^{\circ}}{n}$, where $n$ is the order of rotational symmetry.

Step2: Identify the polygon

The given figure is an equilateral triangle. For an equilateral triangle, the order of rotational symmetry $n = 3$.

Step3: Calculate the angle of rotation

Using the formula $\frac{360^{\circ}}{n}$, substitute $n = 3$. So, $\frac{360^{\circ}}{3}=120^{\circ}$.

Answer:

Order = 3, angle of rotation = 120° (the second option)