Question

1. what is the net force on the refrigerator shown to the right?

Explanation:

Step1: Calculate the net force in the horizontal direction

Forces in the horizontal direction: \(F_{1} = 200N\) (to the right) and \(F_{2}=50N\) (to the left).
The net force in the horizontal direction \(F_{x}=F_{1}-F_{2}\)
\(F_{x}=200 - 50\)
\(F_{x}=150N\) (to the right)

Step2: Calculate the net force in the vertical direction

Forces in the vertical direction: \(F_{3} = 1000N\) (upward) and \(F_{4}=1000N\) (downward).
The net force in the vertical direction \(F_{y}=F_{3}-F_{4}\)
\(F_{y}=1000 - 1000\)
\(F_{y}=0N\)

Step3: Calculate the net force on the refrigerator

The net force \(F=\sqrt{F_{x}^{2}+F_{y}^{2}}\)
Since \(F_{y} = 0\), \(F = F_{x}\)

Answer:

\(150N\) (to the right)