Question

1. what is the midpoint of ab? (-5,-4)(-3,2) ((-5 + -3)/2, (-4 + 2)/2) (-4,-1) 5. what is the length of ab? round your answer to the nearest hundredth.

Explanation:

Step1: Recall distance - formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. From the mid - point calculation in the previous part, we assume the two points $A(-5,-4)$ and $B(-3,2)$. Here $x_1=-5,y_1 = - 4,x_2=-3,y_2 = 2$.

Step2: Substitute values into the formula

First, calculate $(x_2 - x_1)$ and $(y_2 - y_1)$:
$x_2 - x_1=-3-(-5)=-3 + 5 = 2$
$y_2 - y_1=2-(-4)=2 + 4 = 6$
Then, $(x_2 - x_1)^2+(y_2 - y_1)^2=2^2+6^2=4 + 36=40$.
So, $d=\sqrt{40}\approx6.32$.

Answer:

$6.32$