Question

what is the instantaneous velocity at 11 seconds? position vs. time -1 m/s -26 m/s -2.6 m/s -3 m/s -1.5 m/s

Explanation:

Step1: Recall velocity - position relationship

Instantaneous velocity is slope of position - time graph.

Step2: Identify two points on the graph at \(t = 10s\) and \(t = 12s\)

At \(t = 10s\), \(y_1=27m\); at \(t = 12s\), \(y_2 = 24m\).

Step3: Calculate the slope

The slope \(m=\frac{y_2 - y_1}{t_2 - t_1}=\frac{24 - 27}{12 - 10}=\frac{- 3}{2}=-1.5m/s\).

Answer:

-1.5 m/s