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Question
what is the factored form of \\(24x^6 + 3\\)?
\\(3(2x^2 - 1)(4x^4 + 2x^2 + 1)\\)
\\(3(2x^2 + 1)(4x^4 - 2x^2 + 1)\\)
\\((6x^2 + 1)(4x^4 - 6x^2 + 1)\\)
\\((6x^2 - 1)(4x^4 + 6x^2 + 1)\\)
Factor out the greatest common factor
$$
24x^6 + 3 = 3(8x^6 + 1)
$$
Apply the sum of cubes formula
$$
LATEXBLOCK0
$$
Combine the factored components
$$
24x^6 + 3 = 3(2x^2 + 1)(4x^4 - 2x^2 + 1)
$$
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- (A) \(3(2x^2 - 1)(4x^4 + 2x^2 + 1)\)
- (B) \(3(2x^2 + 1)(4x^4 - 2x^2 + 1)\) (Correct answer)
- (C) \((6x^2 + 1)(4x^4 - 6x^2 + 1)\)
- (D) \((6x^2 - 1)(4x^4 + 6x^2 + 1)\)