Question

what is the equation of the line that passes through the point (4, 0) and has a slope of $-\frac{3}{4}$?
answer attempt 1 out of 2

Explanation:

Step1: Recall point-slope form

Point-slope form: $y - y_1 = m(x - x_1)$ where $(x_1,y_1)=(4,0)$, $m=-\frac{3}{4}$

Step2: Substitute values into formula

$y - 0 = -\frac{3}{4}(x - 4)$

Step3: Simplify to slope-intercept form

$y = -\frac{3}{4}x + 3$

Answer:

$y = -\frac{3}{4}x + 3$