Question

1. what is the density of balsa wood if a piece 1.0 cm × 3.0 cm × 2.0 cm has a mass of 96 g? ρ = 96g / 6cm = 16g/cm

Explanation:

Step1: Calculate the volume of the balsa wood

The volume \( V \) of a rectangular prism is given by \( V = l \times w \times h \). Here, \( l = 3.0\space cm \), \( w = 2.0\space cm \), \( h = 1.0\space cm \). So, \( V=3.0\times2.0\times1.0 = 6.0\space cm^3 \)

Step2: Calculate the density

Density \(
ho \) is given by the formula \(
ho=\frac{m}{V} \), where \( m = 96\space g \) and \( V = 6.0\space cm^3 \). So, \(
ho=\frac{96}{6.0}=16\space g/cm^3 \) (Wait, there is a mistake in the original calculation, the correct volume is \( 6.0\space cm^3 \), so \( \frac{96}{6.0} = 16\space g/cm^3 \)? Wait no, wait \( 1.0\times3.0\times2.0=6.0\space cm^3 \), mass is 96g? Wait that would be very dense, but maybe the mass is 9.6g? Wait the original problem says mass of 96g? Wait maybe a typo, but following the given numbers:

Wait the original handwritten has \( \frac{96g}{6cm}=16g/cm \) (probably \( g/cm^3 \)). But let's check the steps again.

Wait, first, volume: length × width × height = \( 1.0\space cm\times3.0\space cm\times2.0\space cm = 6.0\space cm^3 \)

Then density \(
ho=\frac{mass}{volume}=\frac{96\space g}{6.0\space cm^3}=16\space g/cm^3 \) (But in reality, balsa wood density is around 0.16 g/cm³, so maybe the mass is 9.6g? But following the problem as given.)

Answer:

The density of the balsa wood is \( \boldsymbol{16\space g/cm^3} \) (Note: There might be a typo in the mass value as real balsa density is much lower, but based on the given numbers, this is the result.)