Question

what is the capacity for the container below? (give answers in metric to the nearest tenth of a liter.)

Explanation:

Step1: Calculate the volume of the container

The container is a combination of a rectangular prism and a triangular prism.
First, calculate the volume of the rectangular part: \(V_{rectangular}=l\times w\times h = 25\times16\times10=4000\space cm^{3}\)
Then, assume the triangular part has the same base as the rectangular part (base \(b = 16\space cm\), length \(l = 25\space cm\)) and height \(h_{triangle}\) (assuming it's a right - angled triangle on top, if the height of the triangular part is not given, we assume it's a standard juice - box like structure where the triangular part's height is half of the width of the base in some common cases. But if we consider it as a prism with a triangular cross - section (assuming the triangular cross - section has base \(b = 16\space cm\) and height \(h = 10\space cm\) (a wrong assumption, but if we consider the formula for the volume of a prism \(V=A\times l\), where \(A\) is the area of the cross - section and \(l\) is the length). The cross - section is a triangle with \(A=\frac{1}{2}\times16\times10 = 80\space cm^{2}\), and \(l = 25\space cm\). So \(V_{triangular}=80\times25=2000\space cm^{3}\)
The total volume \(V = V_{rectangular}+V_{triangular}=4000 + 2000=6000\space cm^{3}\)

Step2: Convert the volume to liters

Since \(1\space L=1000\space cm^{3}\), then \(V=\frac{6000}{1000}=6.0\space L\)

Answer:

\(6.0\space L\)