Question

1. what is the axis of symmetry: f(x) = 2x² - 6x + 12 x=-1.5 x=1.5 x=7.5 x=-7.5 clear all

Explanation:

Step1: Recall the formula for the axis of symmetry of a quadratic function.

For a quadratic function in the form \( f(x) = ax^2 + bx + c \), the axis of symmetry is given by the formula \( x = -\frac{b}{2a} \).

Step2: Identify the values of \( a \) and \( b \) from the given function.

In the function \( f(x) = 2x^2 - 6x + 12 \), we have \( a = 2 \) and \( b = -6 \).

Step3: Substitute the values of \( a \) and \( b \) into the formula.

Substituting \( a = 2 \) and \( b = -6 \) into \( x = -\frac{b}{2a} \), we get:

$$ x = -\frac{-6}{2 \times 2} = \frac{6}{4} = 1.5 $$

Answer:

\( x = 1.5 \) (corresponding to the option with \( x = 1.5 \))