Question

what is the area of this figure? square meters

Explanation:

Step1: Divide the figure into rectangles

We can divide the given figure into two rectangles. One rectangle with dimensions 9m by 6m and another with dimensions 8m by 3m and a small square - like part with dimensions 1m by 1m.

Step2: Calculate the area of the first rectangle

The area formula for a rectangle is $A = l\times w$. For the rectangle with length $l = 9m$ and width $w = 6m$, the area $A_1=9\times6 = 54m^{2}$.

Step3: Calculate the area of the second rectangle

For the rectangle with length $l = 8m$ and width $w = 3m$, the area $A_2=8\times3 = 24m^{2}$.

Step4: Calculate the area of the small square - like part

The area of a square is $A = s\times s$, where $s = 1m$. So $A_3=1\times1 = 1m^{2}$.

Step5: Calculate the total area of the figure

The total area $A = A_1+A_2 - A_3$ (we subtract the area of the overlapping 1m by 1m part once). $A=54 + 24-1=77m^{2}$.

Answer:

77