Question

what is an alternative way to write the solutions for the compound inequality $x > - 5$ and $x \leq - 2$?

Explanation:

Step1: Analyze the inequality \(x > - 5\)

The inequality \(x > - 5\) can be rewritten as \(-5 < x\).

Step2: Analyze the inequality \(x\leq - 2\)

This inequality remains as \(x\leq - 2\) when considering the compound inequality.

Step3: Combine the two inequalities

Combining \(-5 < x\) and \(x\leq - 2\) gives \(-5 < x\leq - 2\).

Answer:

B. \(-5 < x\leq - 2\)