Question

what do all the multiples of 10 have in common? every multiple of 10 has at least 1 zero at the end of the number and can be written using 10 as a factor? 1 time 2 times

Explanation:

Step1: Recall the definition of multiples

A multiple of a number \( n \) is a number that can be written as \( n\times k \) where \( k \) is an integer. For 10, the multiples are \( 10\times1 = 10 \), \( 10\times2=20 \), \( 10\times3 = 30 \), \( 10\times10=100 \) (which is \( 10\times10 \), so 10 is a factor 2 times here, but the key is the minimum). The general form of a multiple of 10 is \( 10\times k=10^1\times k \), so 10 is a factor at least 1 time (when \( k \) is not a multiple of 10 itself, if \( k \) is a multiple of 10, like \( k = 10 \), then \( 10\times10=100 = 10\times10 \), but the question is about "at least" how many times 10 is a factor. The basic multiple (when \( k = 1 \)) is \( 10=10\times1 \), so 10 is a factor 1 time.

Step2: Analyze the options

The options are "1 time" and "2 times". Since the smallest multiple of 10 (10 itself) can be written as \( 10\times1 \), which means 10 is a factor 1 time. Larger multiples like 20 (\( 10\times2 \)) also have 10 as a factor 1 time (since \( 20=10\times2 \), 10 is a factor once, 2 is the other factor). Even 100 is \( 10\times10 \), but the question is about "at least" how many times, so the minimum is 1 time.

Answer:

1 time