Question

what is ac? use both the distance formula and the law of sines. how do the values compare? explain
using the distance formula, ac=
(type an integer or decimal rounded to two decimal places as needed.)

Explanation:

Step1: Find coordinates of points

Assume \(A(-3,1)\), \(B(3,1)\), \(C(1,6)\)

Step2: Use Distance Formula

The Distance Formula is \(d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\)
For \(A(-3,1)\) and \(C(1,6)\)
\(x_1=-3,y_1 = 1,x_2=1,y_2 = 6\)
\(AC=\sqrt{(1-(-3))^2+(6 - 1)^2}=\sqrt{(4)^2+(5)^2}=\sqrt{16 + 25}=\sqrt{41}\approx6.4\)

Answer:

\(6.4\)