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weeklyquiz - 12 6.1 - 6.3: problem 3
(1 point)
factor:
3a(s - 2t)+5b(s - 2t)+4(s - 2t)=
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Step1: Identify the common factor
The common factor in the expression \(3a(s - 2t)+5b(s - 2t)+4(s - 2t)\) is \((s - 2t)\).
Step2: Factor out the common factor
Using the distributive property \(ac+bc+dc=(a + b + c)c\) (here \(c=(s - 2t)\), \(a = 3a\), \(b = 5b\), \(d = 4\)), we get \((3a + 5b+4)(s - 2t)\)
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\((3a + 5b + 4)(s-2t)\)