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verify the asa postulate for triangle congruence by using congruence tr…

Question

verify the asa postulate for triangle congruence by using congruence transformations.
given: \\( \overline { e k } \cong \overline { l h } \\)
\\( \angle e \cong \angle h \\)
\\( \angle k \cong \angle l \\)
prove: \\( \triangle e k s \cong \triangle h l a \\)
since \\( \angle e \cong \angle h \\), translate \\( \triangle h l a \\) so that points e and h coincide.
next rotate \\( \triangle h l a \\) so that side hl overlaps side ek.
since each vertex in \\( \triangle h l a \\) coincides with its corresponding vertex in the other triangle, there is a congruence transformation that maps \\( \triangle h l a \\) onto the other triangle, so \\( \triangle h l a \cong \triangle \square \\).

Explanation:

Step1: Use congruence transformations

We are given \(\angle E\cong\angle H\), \(\overline{EK}\cong\overline{LH}\), and \(\angle K\cong\angle L\). First, we translate \(\triangle HLA\) so that point \(E\) (from \(\triangle EKS\)) and point \(H\) (from \(\triangle HLA\)) coincide because \(\angle E\cong\angle H\).

Step2: Rotate the triangle

Next, since \(\overline{EK}\cong\overline{LH}\), we rotate \(\triangle HLA\) so that side \(HL\) (from \(\triangle HLA\)) overlaps side \(EK\) (from \(\triangle EKS\)).

Step3: Check vertex - to - vertex correspondence

After the translation and rotation, each vertex in \(\triangle HLA\) coincides with its corresponding vertex in \(\triangle EKS\). By the definition of congruent triangles (if there is a congruence transformation that maps one triangle onto another, the two triangles are congruent), we can say that \(\triangle HLA\cong\triangle EKS\)

Answer:

\(\triangle EKS\)