Question

if the velocity of an object changes from 65 m/s to 98 m/s during a time interval of 12 s, whats the acceleration of the object? a) 13.58 m/s b) 5.42 m/s c) 2.75 m/s d) 33 m/s

Explanation:

Step1: Recall the acceleration formula

Acceleration \( a \) is given by the change in velocity \( \Delta v \) divided by the time interval \( \Delta t \), i.e., \( a=\frac{\Delta v}{\Delta t} \), where \( \Delta v = v_f - v_i \).

Step2: Calculate the change in velocity

The initial velocity \( v_i = 65\space m/s \) and the final velocity \( v_f = 98\space m/s \). So, \( \Delta v=98 - 65=33\space m/s \).

Step3: Calculate the acceleration

The time interval \( \Delta t = 12\space s \). Substitute \( \Delta v = 33\space m/s \) and \( \Delta t = 12\space s \) into the acceleration formula: \( a=\frac{33}{12}=2.75\space m/s^2 \) (Note: The options have a typo in units, it should be \( m/s^2 \) for acceleration, but we follow the calculation).

Answer:

C) 2.75 m/s