Question

value: 2
simplify
\\(\frac{h^{\frac{5}{8}}}{h^{\frac{1}{8}}}\\)
\\(\circ\\) a. \\(h^4\\)
\\(\circ\\) b. \\(h^{\frac{3}{4}}\\)
\\(\circ\\) c. \\(h^{\frac{5}{64}}\\)
\\(\circ\\) d. \\(h^{\frac{1}{2}}\\)

Explanation:

Step1: Apply exponent division rule

When dividing like bases, subtract exponents: $\frac{h^m}{h^n}=h^{m-n}$
So, $\frac{h^{\frac{5}{8}}}{h^{\frac{1}{8}}}=h^{\frac{5}{8}-\frac{1}{8}}$

Step2: Subtract the fractions

Calculate the exponent difference: $\frac{5}{8}-\frac{1}{8}=\frac{4}{8}=\frac{1}{2}$
Result: $h^{\frac{1}{2}}$

Answer:

d. $h^{\frac{1}{2}}$