Question

using the following table, decode the binary ascii code: 01010111 01000010 01001000

Explanation:

Step1: Split the binary code

Split the binary code \(01010111\ 01000010\ 01001000\) into groups of 8 - bit.

Step2: Convert each 8 - bit group

For \(01010111\):
The first 3 bits \(010\) correspond to \(2\) (from the binary - hexadecimal mapping in the table). The next 4 bits \(1011\) correspond to \(B\). But looking at the zone - bit mapping:
The first 3 bits \(010\) (binary) for the zone bits (assuming a certain mapping interpretation, if we consider the 8 - bit as a combination of zone and digit bits in a non - standard (but table - based) way).
If we consider the 8 - bit code \(01010111\):
The first 3 bits \(010\) (binary) for the zone (if we assume zone is the first 3 bits). The remaining 5 bits \(10111\). But using the table's zone - bit and digit - bit combination (a bit of a stretch, but re - interpreting the table as a way to map 8 - bit to characters):
Another approach: If we consider the 8 - bit code as a combination of the zone (first 3 bits) and the digit (last 5 bits).
The first 3 bits \(010\) (binary) for zone (row) and the last 5 bits \(10111\) (binary). But \(10111\) (binary) \(= 23\) (decimal). However, looking at the table's structure (assuming a different mapping where we split the 8 - bit into two parts: the first 3 bits as a 'zone' index and the last 5 bits as a 'digit' index in a non - standard table use).
Alternatively, if we use the standard ASCII decoding (but the table seems to be a hex - zone - bit mapping). Let's assume the 8 - bit code is split as follows:
For \(01010111\):
The first 3 bits \(010\) (binary) \(=2\) (hexadecimal). The next 5 bits \(10111\) (binary) \(= 23\) (decimal). But using the table's zone - bit and digit - bit combination (a more intuitive way, assume the 8 - bit is split into \(010\) (zone) and \(10111\) (digit) in a non - standard table usage. But a better way is to use the fact that \(01010111\) (binary) \(=87\) (decimal). ASCII code \(87\) is 'W'.
For \(01000010\):
\(01000010\) (binary) \(=66\) (decimal). ASCII code \(66\) is 'B'.
For \(01001000\):
\(01001000\) (binary) \(=72\) (decimal). ASCII code \(72\) is 'H'.

Answer:

WHB