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use the unit circle to find the value of each trigonometric function at…

Question

use the unit circle to find the value of each trigonometric function at the angle indicated. cos(270°)= sin(270°)= -1 tan(270°)= 0 cos(0°)= 1 sin(0°)= tan(0°)=

Explanation:

Step1: Recall unit - circle definitions

On the unit circle, for an angle \(\theta\), \(\cos\theta=x\) - coordinate of the point on the unit circle corresponding to \(\theta\), \(\sin\theta = y\) - coordinate of the point on the unit circle corresponding to \(\theta\), and \(\tan\theta=\frac{\sin\theta}{\cos\theta}\).

Step2: Find values for \(\theta = 270^{\circ}\)

For \(\theta = 270^{\circ}\), the point on the unit circle is \((0,-1)\). So, \(\cos(270^{\circ})=0\), \(\sin(270^{\circ})=-1\), and \(\tan(270^{\circ})=\frac{\sin(270^{\circ})}{\cos(270^{\circ})}=\frac{-1}{0}\) (undefined).

Step3: Find values for \(\theta = 0^{\circ}\)

For \(\theta = 0^{\circ}\), the point on the unit circle is \((1,0)\). So, \(\cos(0^{\circ}) = 1\), \(\sin(0^{\circ})=0\), and \(\tan(0^{\circ})=\frac{\sin(0^{\circ})}{\cos(0^{\circ})}=\frac{0}{1}=0\).

Answer:

\(\cos(270^{\circ}) = 0\), \(\sin(270^{\circ})=-1\), \(\tan(270^{\circ})\) is undefined, \(\cos(0^{\circ}) = 1\), \(\sin(0^{\circ})=0\), \(\tan(0^{\circ}) = 0\)