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use the partial quotients method to find 985 ÷ 28. fill in the missing …

Question

use the partial quotients method to find 985 ÷ 28. fill in the missing numbers.

Explanation:

Step1: First partial - quotient

We know that \(28\times10 = 280\). We subtract \(280\) from \(985\) three times. \(985-280 = 705\), \(705 - 280=425\), \(425 - 280 = 145\). Each time we subtract \(280\), the partial - quotient is \(10\).

Step2: Last partial - quotient

Since \(145-140=5\) and \(140\div28 = 5\).

Step3: Calculate the total quotient

The total quotient is \(10 + 10+10 + 5=35\) and the remainder is \(5\).

Answer:

The quotient is \(35\) and the remainder is \(5\). In the long - division form:

  • The first box above the division symbol: \(35\)
  • The box for the remainder: \(5\)
  • The box next to the first \(280\): \(10\)
  • The box next to the second \(280\): \(10\)
  • The box next to the third \(280\): \(10\)
  • The box next to the \(140\): \(5\)
  • The boxes for the sub - tractions results: \(705\), \(425\), \(145\), \(5\) (from top to bottom)