Question

use the partial quotients method to find 2,356 ÷ 62. fill in the missing numbers.

Explanation:

Step1: First partial - quotient

We know that $62\times10 = 620$. We subtract $620$ from $2356$ multiple times. $2356\div62$, we first consider how many times $620$ (i.e., $10\times62$) can go into $2356$.
$2356-620 = 1736$.

Step2: Second partial - quotient

Subtract another $620$ from $1736$. $1736 - 620=1116$.

Step3: Third partial - quotient

Subtract another $620$ from $1116$. $1116-620 = 496$.

Step4: Fourth partial - quotient

Now we find how many times $62$ goes into $496$. Since $496\div62 = 8$.
The sum of the partial - quotients is $10 + 10+10 + 8=38$. And $2356=38\times62+0$.

Answer:

The quotient is $38$ and the remainder is $0$. The blanks are filled as follows:
The quotient box at the top is $38$.
For the long - division steps:
The first $620$ is $10\times62$, the second $620$ is $10\times62$, the third $620$ is $10\times62$, and the $496$ is $8\times62$. The remainder box at the top is $0$.