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use the nth term test for divergence to show that the series is diverge…

Question

use the nth term test for divergence to show that the series is divergent, or state that the test is inconclusive
sum _ { n = 0 } ^ { infty } \frac { 1 } { n + 14 }
select the correct choice below and, if necessary, fill in the answer box within your choice
a. the series diverges because ( lim _ { n
ightarrow infty } \frac { 1 } { n + 14 } ) exists and is equal to
b. the series diverges because ( lim _ { n
ightarrow infty } \frac { 1 } { n + 14 } = infty ) and fails to exist
c. the series diverges because ( lim _ { n
ightarrow infty } \frac { 1 } { n + 14 } = - infty ) and fails to exist
d. the test is inconclusive because ( lim _ { n
ightarrow infty } \frac { 1 } { n + 14 } = )

Explanation:

Step1: Find the limit of the general term

We need to find \(\lim_{n
ightarrow\infty}\frac{1}{n + 14}\).
Divide both the numerator and denominator by \(n\):
\(\lim_{n
ightarrow\infty}\frac{\frac{1}{n}}{1+\frac{14}{n}}\)

Step2: Evaluate the limit

As \(n
ightarrow\infty\), \(\lim_{n
ightarrow\infty}\frac{1}{n}=0\) and \(\lim_{n
ightarrow\infty}\frac{14}{n}=0\).
So, \(\lim_{n
ightarrow\infty}\frac{\frac{1}{n}}{1+\frac{14}{n}}=\frac{0}{1 + 0}=0\).
But according to the \(n\) - th term test for divergence: If \(\sum_{n = 0}^{\infty}a_{n}\) is a series and \(\lim_{n
ightarrow\infty}a_{n}
eq0\), the series diverges. If \(\lim_{n
ightarrow\infty}a_{n}=0\), the test is inconclusive.

Answer:

D. The test is inconclusive because \(\lim_{n
ightarrow\infty}\frac{1}{n + 14}=0\)