Question

use a graph to solve the inequality.
$x^2 - x - 12 > 0$

graph the equation $y = x^2 - x - 12$ by plotting points. complete the following table.

$x$	$x^2 - x - 12$
$-1$	$-10$
$0$	$square$
$1$	$square$
$2$	$square$

Explanation:

Step1: Calculate for x=0

Substitute \( x = 0 \) into \( y = x^2 - x - 12 \).
\( y = 0^2 - 0 - 12 = -12 \)

Step2: Calculate for x=1

Substitute \( x = 1 \) into \( y = x^2 - x - 12 \).
\( y = 1^2 - 1 - 12 = 1 - 1 - 12 = -12 \)

Step3: Calculate for x=2

Substitute \( x = 2 \) into \( y = x^2 - x - 12 \).
\( y = 2^2 - 2 - 12 = 4 - 2 - 12 = -10 \)

Answer:

For \( x = 0 \): \(-12\)
For \( x = 1 \): \(-12\)
For \( x = 2 \): \(-10\)