Question

use the graph of the function to complete the table.
input | output
-4 |
-3 | 5
-1 |

Explanation:

Step1: Find output for x = -4

Locate x = -4 on the x - axis. Then, find the corresponding y - value (output) on the graph. From the graph, when x = -4, the y - value is 8.

Step2: Find output for x = -1

Locate x = -1 on the x - axis. Then, find the corresponding y - value (output) on the graph. From the graph, when x = -1, the y - value is 0 (since the graph crosses the x - axis at x=-1? Wait, no, looking at the graph, when x = -1, let's check again. Wait, the graph at x=-1: let's see the grid. Wait, maybe I made a mistake. Wait, the graph: when x=-1, let's see the curve. Wait, maybe the graph at x=-1: let's check the coordinates. Wait, the table has x=-3 with output 5. For x=-4: looking at the graph, the point at x=-4 is ( - 4, 8) as the upper part. For x=-1: let's see, when x=-1, the graph is at y=0? Wait, no, the graph crosses the x - axis at x=0? Wait, no, the graph crosses the y - axis at (0, - 2)? Wait, maybe I misread. Wait, the input x=-4: the upper curve at x=-4, the y - coordinate is 8. For x=-1: let's see, the graph at x=-1: let's check the grid. Each square is 1 unit. So x=-1, moving up from x=-1, the graph at x=-1: let's see, the curve at x=-1: maybe y=0? Wait, no, maybe I need to re - examine. Wait, the table has x=-3, output 5. So for x=-4: the upper part of the graph (the left - hand curve) at x=-4 is at y=8. For x=-1: let's see, when x=-1, the graph (the lower curve? Wait, no, there are two parts? Wait, the graph has a curve coming from the left (x < - 2) and a curve going down (x > - 2). Wait, at x=-4, it's the left curve, y=8. At x=-1, it's the right curve? Wait, no, x=-1 is between - 2 and 0. Wait, maybe the graph at x=-1: let's see, the y - value when x=-1. Let's check the grid. So x=-1, y=0? Wait, maybe not. Wait, perhaps the correct values:

Wait, let's start over. The table has input - 4, - 3 (output 5), - 1.

For x=-4: look at the graph, the point with x=-4: the y - coordinate is 8 (since the upper curve at x=-4 is at y=8).

For x=-1: look at the graph, when x=-1, the y - coordinate is 0 (because the graph crosses the x - axis at x=-1? Wait, no, the graph crosses the x - axis at x=0? Wait, no, the x - axis is y=0. So when x=-1, is the graph at y=0? Let's see the grid. Each square is 1 unit. So x=-1, y=0.

Wait, maybe the correct outputs:

For x=-4: output is 8.

For x=-1: output is 0.

Answer:

For x = - 4, output is 8; for x=-1, output is 0. So the completed table (partial) is:

Input (x)	Output (y)
- 3	5
- 1	0