Question

1. use the graph to answer the follow questions:vertex: (2,1)y - intercept: - 3circle one: max / minaxis of symmetry: 2bonus: write the equation of the line in vertex form:f(x)=

Explanation:

Step1: Recall the vertex form of a parabola

The vertex form of a parabola is \(y = a(x - h)^{2}+k\), where \((h,k)\) is the vertex of the parabola. Given the vertex \((h,k)=(2,1)\), the equation becomes \(y=a(x - 2)^{2}+1\).

Step2: Find the value of \(a\)

The \(y\) - intercept is the point where \(x = 0\). Substitute \(x = 0\) and \(y=-3\) into the equation \(y=a(x - 2)^{2}+1\).

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Answer:

The equation of the parabola in vertex form is \(y=-(x - 2)^{2}+1\)