Question

use the given point, p, on the unit circle to find the value of sine and cosine of t.
p is at the point (-0.3384, 0.941).
sin(t)=
cos(t)=
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Explanation:

Step1: Recall the unit - circle definitions

On the unit circle \(x^{2}+y^{2}=1\), for a point \(P=(x,y)\) corresponding to an angle \(t\), \(\sin(t)=y\) and \(\cos(t)=x\).

Step2: Identify \(x\) and \(y\) values

Given the point \(P=(- 0.3384,0.941)\), here \(x=-0.3384\) and \(y = 0.941\).

Answer:

\(\sin(t)=0.941\)
\(\cos(t)=-0.3384\)