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use the given coordinates to compute the perimeter of the triangle. rou…

Question

use the given coordinates to compute the perimeter of the triangle. round your answer to the nearest tenth
(1 point)
the perimeter is approximately □ units.

Explanation:

Step1: Calculate the length of \( PR \)

Use the distance formula for horizontal line (\( y - \)coordinates are the same). \( PR=\vert x_{P}-x_{R}\vert=\vert1 - (-4)\vert = 5\)

Step2: Calculate the length of \( PQ \)

Use the distance formula for vertical line (\( x - \)coordinates are the same). \( PQ=\vert y_{Q}-y_{P}\vert=\vert6 - 2\vert = 4\)

Step3: Calculate the length of \( QR \)

Use the distance formula \( d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\). Here \( x_{1}=-4,y_{1}=2,x_{2}=1,y_{2}=6\).
\( QR=\sqrt{(1 - (-4))^{2}+(6 - 2)^{2}}=\sqrt{5^{2}+4^{2}}=\sqrt{25 + 16}=\sqrt{41}\approx6.4\)

Step4: Calculate the perimeter

Perimeter \(=PR + PQ+QR\). Substitute the values: \(5 + 4+6.4 = 15.4\)

Answer:

\(15.4\)