Question

use this equation to calculate the specific heat capacity of each metal:
$c_{metal} = \frac{c_{water} \\, m_{water} \\, \delta t_{water}}{m_{metal} \\, \delta t_{metal}}$
$c_{water}$ = sp. heat capacity of water (4.18 j/g°c)
$m_{water}$ = mass of the water in the cup
$\delta t_{water}$ = change in water temperature
$m_{metal}$ = mass of the metal
$\delta t_{metal}$ = change in metal temperature
record these values in table b of your student guide.
what is the specific heat for the aluminum wire?
\boxed{} j/g°c
what is the specific heat for the steel wire?
\boxed{} j/g°c
what is the specific heat for the lead pellets?
\boxed{} j/g°c

Explanation:

To calculate the specific heat capacity of each metal, we need the values of \( m_{\text{water}} \), \( \Delta T_{\text{water}} \), \( m_{\text{metal}} \), and \( \Delta T_{\text{metal}} \) for each metal (aluminum wire, steel wire, lead pellets). Since these values are not provided in the question, we can't perform the calculation directly. However, we can recall the standard specific heat capacities:

• For aluminum, the specific heat capacity \( c_{\text{aluminum}} \approx 0.90 \, \text{J/g°C} \)
• For steel, the specific heat capacity \( c_{\text{steel}} \approx 0.45 \, \text{J/g°C} \)
• For lead, the specific heat capacity \( c_{\text{lead}} \approx 0.13 \, \text{J/g°C} \)

These values are standard and can be used if the experimental data aligns with the theoretical values.

Step1: Recall Standard Specific Heats

Aluminum: \( c \approx 0.90 \, \text{J/g°C} \)
Steel: \( c \approx 0.45 \, \text{J/g°C} \)
Lead: \( c \approx 0.13 \, \text{J/g°C} \)

Answer:

• Specific heat for aluminum wire: \( \boldsymbol{0.90} \, \text{J/g°C} \)
• Specific heat for steel wire: \( \boldsymbol{0.45} \, \text{J/g°C} \)
• Specific heat for lead pellets: \( \boldsymbol{0.13} \, \text{J/g°C} \)