Question

use the distributive property to simplify the following fraction.\\(\frac{12g + 8h}{4gh}\\)\
a \\(\frac{2}{h} + \frac{3}{g}\\)\
b \\(\frac{4}{h} - \frac{2}{g}\\)\
c \\(\frac{3}{h} + \frac{2}{g}\\)

Explanation:

Step1: Apply Distributive Property

The fraction is \(\frac{12g + 8h}{4gh}\). Using the distributive property of division over addition (\(\frac{a + b}{c}=\frac{a}{c}+\frac{b}{c}\)), we split the numerator: \(\frac{12g}{4gh}+\frac{8h}{4gh}\).

Step2: Simplify Each Term

For \(\frac{12g}{4gh}\), cancel \(g\) and divide \(12\) by \(4\): \(\frac{12}{4h}=\frac{3}{h}\). For \(\frac{8h}{4gh}\), cancel \(h\) and divide \(8\) by \(4\): \(\frac{8}{4g}=\frac{2}{g}\). So the simplified form is[SSE Completed, Client Connection Error][SSE onError error]

Answer:

Step1: Apply Distributive Property

The fraction is \(\frac{12g + 8h}{4gh}\). Using the distributive property of division over addition (\(\frac{a + b}{c}=\frac{a}{c}+\frac{b}{c}\)), we split the numerator: \(\frac{12g}{4gh}+\frac{8h}{4gh}\).

Step2: Simplify Each Term

For \(\frac{12g}{4gh}\), cancel \(g\) and divide \(12\) by \(4\): \(\frac{12}{4h}=\frac{3}{h}\). For \(\frac{8h}{4gh}\), cancel \(h\) and divide \(8\) by \(4\): \(\frac{8}{4g}=\frac{2}{g}\). So the simplified form is[SSE Completed, Client Connection Error][SSE onError error]