QUESTION IMAGE
Question
use the distance formula to find the lengths of the sides of the quadrilateral. express your answers in simplest radical form or fractions where applicable or appropriate.
| statements | reasons |
|---|---|
| 2. kl = units | 2. distance formula |
| lm = units | |
| mn = units | |
| nk = units |
Step1: Recall distance formula
The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$.
Step2: Calculate length of $KL$
For points $K(1,5)$ and $L(6,7)$, $x_1 = 1,y_1 = 5,x_2=6,y_2 = 7$. Then $KL=\sqrt{(6 - 1)^2+(7 - 5)^2}=\sqrt{25 + 4}=\sqrt{29}$ units.
Step3: Calculate length of $LM$
For points $L(6,7)$ and $M(7,3)$, $x_1 = 6,y_1 = 7,x_2=7,y_2 = 3$. Then $LM=\sqrt{(7 - 6)^2+(3 - 7)^2}=\sqrt{1+16}=\sqrt{17}$ units.
Step4: Calculate length of $MN$
For points $M(7,3)$ and $N(3,1)$, $x_1 = 7,y_1 = 3,x_2=3,y_2 = 1$. Then $MN=\sqrt{(3 - 7)^2+(1 - 3)^2}=\sqrt{16 + 4}=\sqrt{20}=2\sqrt{5}$ units.
Step5: Calculate length of $NK$
For points $N(3,1)$ and $K(1,5)$, $x_1 = 3,y_1 = 1,x_2=1,y_2 = 5$. Then $NK=\sqrt{(1 - 3)^2+(5 - 1)^2}=\sqrt{4 + 16}=\sqrt{20}=2\sqrt{5}$ units.
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$KL=\sqrt{29}$ units, $LM=\sqrt{17}$ units, $MN = 2\sqrt{5}$ units, $NK=2\sqrt{5}$ units