Question

use the diagram and the drop - down menu to answer the question. if bulb c burns out, what will happen to bulbs a and b?

Explanation:

The circuit is a series circuit (bulbs A, B, C are in a single path). In a series circuit, the current is the same through all components, and if one component (like bulb C) fails (burns out), the circuit becomes open, so current stops flowing. Thus, bulbs A and B will also go out (stop working) because there's no complete circuit for current to pass through.

Answer:

Bulbs A and B will also go out (stop functioning) because the circuit is series, and a break in one component (bulb C burning out) breaks the entire circuit, preventing current from flowing through A and B.