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use the box method to distribute and simplify (-6 + 2x)(6x - 6x^2 + 5 -…

Question

use the box method to distribute and simplify (-6 + 2x)(6x - 6x^2 + 5 - 6x^3). drag and drop the terms to the correct locations of the table. (-6 + 2x)(6x - 6x^2 + 5 - 6x^3) 6x - 6x^2 5 - 6x -6 2x answer attempt 1 out of 2 you must answer all questions above in order to submit.

Explanation:

Step1: Multiply -6 by each term

$-6\times6x=- 36x$, $-6\times(-6x^{2}) = 36x^{2}$, $-6\times5=-30$, $-6\times(-6x^{3}) = 36x^{3}$

Step2: Multiply 2x by each term

$2x\times6x = 12x^{2}$, $2x\times(-6x^{2})=-12x^{3}$, $2x\times5 = 10x$, $2x\times(-6x^{3})=-12x^{4}$

The filled - in table:

$6x$$-6x^{2}$$5$$-6x^{3}$
$2x$$12x^{2}$$-12x^{3}$$10x$$-12x^{4}$

To simplify the product $(-6 + 2x)(6x-6x^{2}+5 - 6x^{3})$, we combine like - terms:
\[

$$\begin{align*} &-12x^{4}+(36x^{3}-12x^{3})+(36x^{2}+12x^{2})+(-36x + 10x)-30\\ =&-12x^{4}+24x^{3}+48x^{2}-26x - 30 \end{align*}$$

\]

Answer:

The filled - in table:

$6x$$-6x^{2}$$5$$-6x^{3}$
$2x$$12x^{2}$$-12x^{3}$$10x$$-12x^{4}$

The simplified product is $-12x^{4}+24x^{3}+48x^{2}-26x - 30$