Question

universal gravitation practice

g=the universal gravitational
constant
6.67 x 10^-11

1. the gravitational force between two objects is 15n. if the

distance between the two objects is cut in half, then the
new force would be:

1. the gravitational force between two objects is 15n. if the

distance between them is doubled, then the new force
would be:

1. the gravitational force between two objects is 15n. if the

distance between them is tripled, then the new force
would be:

1. the gravitational force between two objects is 15n. if the

distance between them is quadrupled, then the new
force would be:

1. the gravitational force between two objects is 15n. if the

mass of one of the objects is doubled, then the new force
would be:

1. the gravitational force between two objects is 15n. if the

mass of one object is doubled while the mass of the
second object is tripled, the new force would
be:

1. mr. higley, whos mass is 100kg, is doing a physics

demonstration in the front of the classroom. how much
gravitational force does he exert on a 50kg student sitting
3 meters away?

1. the force of gravity between jupiter and its moon,

ganymede, is 1.638 x 10^22n. if the mass of jupiter is 1.9 x
10^27 kg and the mass of ganymede is 1.48 x 10^23 kg, how
far apart are they?

1. using force on the y axis and distance on the x axis, show

a graph for the relationship between gravitational force
and distance.

Explanation:

Step1: Analyze the change in distance

The formula for gravitational force is \( F=\frac{Gm_1m_2}{d^2} \). When the distance \( d \) is cut in half (\( d'=\frac{d}{2} \)), the new force \( F'=\frac{Gm_1m_2}{(d')^2}=\frac{Gm_1m_2}{(\frac{d}{2})^2} \).

Step2: Simplify the expression

\( F' = 4\times\frac{Gm_1m_2}{d^2} \). Since the original force \( F = 15N=\frac{Gm_1m_2}{d^2} \), then \( F'=4F \).

Answer:

\( 60N \)