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Question
unit 2 lessons 18 to 20 swyk
which graph represents the solution to $\frac{1}{4}x + 3 < \frac{7}{8}x - 2$
Step1: Eliminate the fraction
Multiply each term of the inequality \(\frac{1}{4}x + 3<\frac{7}{8}x-2\) by \(8\) (the least - common multiple of \(4\) and \(8\)) to get \(2x + 24<7x-16\).
Step2: Move the \(x\) - terms to one side and constants to the other side
Subtract \(2x\) from both sides: \(24<7x - 2x-16\), which simplifies to \(24<5x-16\). Then add \(16\) to both sides: \(24 + 16<5x\), so \(40<5x\).
Step3: Solve for \(x\)
Divide both sides by \(5\): \(\frac{40}{5}
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The graph with an open circle at \(8\) and an arrow pointing to the right (the second option from the bottom in the given set of graphs).