Question

um ponto é escolhido aleatoriamente dentro do retângulo abaixo. qual é a probabilidade de que o ponto esteja dentro do triângulo? (a figura pode não estar desenhada em escala). 28 13 8 14 show your work here enter your answer check

Explanation:

Step1: Calculate rectangle area

The area formula for a rectangle is $A = l\times w$. Here, $l = 28$ and $w=13$, so $A_{rectangle}=28\times13 = 364$.

Step2: Calculate triangle area

The area formula for a triangle is $A=\frac{1}{2}\times b\times h$. Here, $b = 14$ and $h = 8$, so $A_{triangle}=\frac{1}{2}\times14\times8=56$.

Step3: Calculate probability

The probability $P$ that a randomly - chosen point in the rectangle is in the triangle is given by the ratio of the area of the triangle to the area of the rectangle. So $P=\frac{A_{triangle}}{A_{rectangle}}=\frac{56}{364}=\frac{2}{13}$.

Answer:

$\frac{2}{13}$