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two solutions of different concentrations of acid are mixed creating 40…

Question

two solutions of different concentrations of acid are mixed creating 40 ml of a solution that is 32% acid. one-quarter of the solution is made up of a 20% acid solution. the remaining three-quarters is made up of a solution of unknown concentration, c.

which equation can be used to determine c, the unknown concentration?

\\(30c + 10(0.2) = 40(0.32)\\)

\\(\frac{3}{4}(c) +
\frac{1}{4}(0.2) = 40(0.32)\\)

\\(\frac{3}{4}(c)(\frac{1}{4}(0.2)) = 40(0.32)\\)

\\(30(c)(10(0.2)) = 40(0.32)\\)

Explanation:

Identify given values and volumes

Using the Algebraic Modeling knowledge point

$$ LATEXBLOCK0 $$

Formulate the mixture equation

Using the Algebraic Modeling knowledge point

$$ LATEXBLOCK1 $$

Compare with the given options

Using the Algebraic Modeling knowledge point

$$ LATEXBLOCK2 $$

Answer:

  • (A) \(30c + 10(0.2) = 40(0.32)\) (Correct answer)
  • (B) \(\frac{3}{4}(c) + \frac{1}{4}(0.2) = 40(0.32)\)
  • (C) \(\frac{3}{4}(c)(\frac{1}{4}(0.2)) = 40(0.32)\)
  • (D) \(30(c)(10(0.2)) = 40(0.32)\)